C++ help please?

Consider the following function definition:


void defaultParam(int u, int v = 5, double z = 3.2)


{


int a;


u = u + static_cast%26lt;int%26gt;(2 * v + z);


a = u + v * z;


cout %26lt;%26lt; "a = " %26lt;%26lt; a %26lt;%26lt; endl;


}


What is output of the following function calls?


a. defaultParam(6);


b. defaultParam(3, 4);


c. defaultParam(3, 0, 2.8);

C++ help please?
I provided tracing steps so you can understand what is going on.





a: u = 6, v = 5, z = 3.2


u = 6 + int(2 * 5 + 3.2) = 6 + 13 = 19


a = 19 + 5 * 3.2 = 19 + 16 = 35.


"a = 35"


b: u = 3, v = 4, z = 3.2


u = 3 + int(2 * 4 + 3.2) = 3 + 11 = 14


a = 14 + 4 * 3.2 = 14 + 12.8 = (int) 26.8 = 26


"a = 26"


c: u = 3, v = 0, z = 2.8


u = 3 + int(2 * 0 + 2.8) = 3 + int(2.8) = 5


a = 5 + 0 * 2.8 = 5


"a = 5"
Reply:Dude. Why don't you just type it in, compile it, and run it with those arguments??? Do you own homework!
Reply:Plug in the numbers.


With out a call just using what is in the parameters, I get 29.


So, substitute the 6 for the u and do the math


then etc.....
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